 Solution

ID: past-exam-of-the-physics-2-paper-of-the-university-of-oxford/2014-resit/8/1/solution

\nabla \cdot D = ρ_{free}, \oint_{\partial V} D \cdot d S = Q_{free, enclosed} .

The area normal points out of

V

D = ϵ_{0} E

, so these become

\nabla \cdot E = ρ / ϵ_{0}

and

\oint E \cdot d S = Q_{enclosed} / ϵ_{0}

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