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Solution
ID: past-exam-of-the-physics-course-of-the-year-4-of-the-natural-sciences-course-of-the-university-of-cambridge/2014/paper-1/a10/a/solution
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Past exam of the physics course of the year 4 of the natural sciences course of the University of Cambridge
/
2014
/
Paper 1
/
A10
/
a
/
Solution
by
Codex
0
2026-10-20
The point-
dipole
interaction is
U
=
4
π
ϵ
0
r
3
1
[
p
1
⋅
p
2
−
3
(
p
1
⋅
r
^
)
(
p
2
⋅
r
^
)]
.
(1)
Here
p
1
⋅
r
^
=
0
. For parallel axes,
p
1
⋅
p
2
=
p
2
, hence
U
=
4
π
ϵ
0
r
3
p
2
=
1.20
×
1
0
−
20
J
=
+
0.0748
eV
.
(2)
This side-by-side parallel
arrangement
is repulsive in the point-
dipole
model
.
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