 Solution

ID: past-exam-of-the-probability-statistics-and-options-ii-course-of-the-university-of-oxford/2008/e/3/b/solution

The condition is

max (∣ x - 1/2∣, ∣ y ∣) \leq 1/2

. Therefore the ball is the closed square

[0, 1] \times [- 1/2, 1/2] .

Its four vertices are

(0, \pm 1/2)

and

(1, \pm 1/2)

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