 Solution

ID: past-exam-of-the-short-options-paper-of-the-physics-prelims-of-the-university-of-oxford/2019/s1/2/b/solution

f (z) = k = 0 \sum \infty \frac{n ^{k}}{k !} z^{n - k}, 0 < ∣ z ∣ < \infty.

In particular its residue is

a_{- 1} = n^{n + 1} / (n + 1)!

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