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Solution
ID: past-exam-of-the-short-options-paper-shared-by-prelims-and-parts-a-and-b-of-the-physics-course-of-the-university-of-oxford/2012/s18/3/2/solution
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Past exam of the short options paper shared by Prelims and Parts A and B of the physics course of the University of Oxford
/
2012
/
S18
/
3
/
2
/
Solution
by
Codex
0
2026-10-25
For dependence on
z
alone and constant
V
0
, remove the common phase by
ψ
=
e
−
i
V
0
t
ψ
. Then
∂
t
ψ
=
−
σ
z
∂
z
ψ
. The normalized
eigenvectors
u
+
=
(
1
0
)
,
u
−
=
(
0
1
)
(1)
obey
σ
z
u
±
=
±
u
±
. The corresponding
first
-order
transport equations
have characteristics
t
−
z
and
t
+
z
, respectively,
giving
ψ
(
z
,
t
)
=
e
−
i
V
0
t
[
η
(
t
−
z
)
u
+
+
ρ
(
t
+
z
)
u
−
]
.
(2)
Here
η
propagates toward
+
z
and
ρ
toward
−
z
, both at unit
speed
.
For
a
fixed
unit vector
n
^
, replace
z
by
n
^
⋅
x
and choose orthonormal
spinors
satisfying
(
σ
⋅
n
^
)
u
±
(
n
^
)
=
±
u
±
(
n
^
)
. If
n
^
=
(
sin
ϑ
cos
φ
,
sin
ϑ
sin
φ
,
cos
ϑ
)
, one
choice
is
u
+
(
n
^
)
=
(
cos
(
ϑ
/2
)
e
i
φ
sin
(
ϑ
/2
)
)
,
u
−
(
n
^
)
=
(
−
e
−
i
φ
sin
(
ϑ
/2
)
cos
(
ϑ
/2
)
)
.
(3)
Independent constant phases on the
spinors
can be absorbed into the two arbitrary envelope
functions
.
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