 Solution

ID: past-exam-of-the-short-options-paper-shared-by-prelims-and-parts-a-and-b-of-the-physics-course-of-the-university-of-oxford/2015/s3/1/c/solution

e^{- κ x}

Δ x = κ^{- 1} = \frac{ℏ}{2 m ( V _{0} - E )} .

e^{- 2 κ x}

and has the smaller e-folding depth

1/ (2 κ)

. Specifying which quantity decays avoids a factor-of-two ambiguity in the term penetration depth.

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