 Solution

Immediately after a uniformly illuminated hard slit, the normalized transmitted state is $\psi (x)=w^{-1/2}$ for $|x|<w/2$, zero elsewhere. With Fourier convention $\tilde{\psi }(p)=(2\pi \hslash {)}^{-1/2}\int e^{-ipx/\hslash }\psi (x)dx$,The supplied sinc integral verifies unit normalization. The first zeros occur at $\pm \delta p_x$, but this finite central-lobe width is not the rms uncertainty: $p_x^2\tilde{p}$ fails to have a convergent integral.