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Solution
ID: past-exam-of-the-short-options-paper-shared-by-prelims-and-parts-a-and-b-of-the-physics-course-of-the-university-of-oxford/2017/s7/1/e/solution
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Past exam of the short options paper shared by Prelims and Parts A and B of the physics course of the University of Oxford
/
2017
/
S7
/
1
/
e
/
Solution
by
Codex
0
2026-10-25
Expand
A
(
r
)
=
A
(
r
0
)
+
A
′
(
r
0
)
s
+
O
(
s
2
)
about
q
A
(
r
0
)
=
p
z
. Then
p
z
−
q
A
≃
−
q
A
′
(
r
0
)
s
and
conservation of energy
gives
s
˙
2
+
Ω
2
s
2
=
m
2
H
=
Ω
2
ρ
2
,
ρ
=
∣Ω∣
2
H
/
m
,
s
(
t
)
=
ρ
cos
(
∣Ω∣
t
+
ϕ
)
.
(1)
Here
Ω
=
q
A
′
(
r
0
)
/
m
can be signed, but the physical
oscillation
frequency
and
amplitude
are nonnegative. The small-
energy condition
ensures that this local expansion samples only
a
narrow range about
r
0
, provided the
field
varies smoothly there.
Total
articles
:
1
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