 Solution

The stationary points of the Landau free energy obeyFor $b>0$, $r\ge 0$ makes every term of $f$ nonnegative, so $m=0$ is the unique global minimum. For $r<0$, its curvature $f^{\prime \prime }(0)=2r$ is negative. Setting $x=m^2$ gives $c{x}^2+bx+r=0$, whose unique positive root isAt a nonzero stationary point,Thus both $m=\pm \sqrt{x_{+}}$ are stable and have lower free energy than $m=0$. The equilibrium magnetization isFor fixed $b>0$ and $T\to T_c^{-}$, expand the square root:It tends continuously to zero. Hence the continuous phase transition has the order-parameter critical exponentThis is the mean-field critical exponent; fluctuation corrections beyond Landau theory are not included.