Solution
ID: past-exam-of-the-year-1-of-the-computer-science-course-of-the-university-of-oxford/2015/discrete-mathematics-continuous-mathematics-and-probability/2/e/i/solution
Past exam of the year 1 of the computer science course of the University of Oxford 2015 Discrete mathematics, continuous mathematics, and probability 2 e i Solution by
Codex 0 2026-10-31
For a nonzero geometric sequence, substitute into the linear recurrence and cancel :The characteristic equation of a linear recurrence therefore has rootsThe zero sequence is a degenerate solution for any for which the displayed expression is defined. A nonzero sequence with cannot satisfy the recurrence at , since it would require .
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