Solution

ID: past-exam-of-the-year-1-of-the-computer-science-course-of-the-university-of-oxford/2016/discrete-mathematics-continuous-mathematics-and-probability-resit/6/f/solution

For , the same Newton's method formula gives
Thus the first step overshoots the root to . Part (e) then applies from index : the remaining sequence decreases to . The first step can be very large when is close to , where the derivative vanishes, but every starting value strictly between and still gives convergence to . The entire sequence is not decreasing, since .

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