 Solution

ID: past-exam-of-the-year-1-of-the-computer-science-course-of-the-university-of-oxford/2017/discrete-mathematics-continuous-mathematics-and-probability/2/a/i/solution

801 \equiv 1

32 \cdot 19 \equiv 0

, and

29 \cdot 13 \equiv 5 \cdot 5 \equiv 1

. The squared difference is consequently congruent to one, giving the remainder

2.

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