Solution

ID: past-exam-of-the-year-1-of-the-computer-science-course-of-the-university-of-oxford/2019/functional-programming-design-and-analysis-of-algorithms/3/d/solution

Construct each possible winning line, then test whether one is contained in the player's occupancy set:
winningLines :: [Places]
winningLines =
  [[(r,c) | c <- [0..2]] | r <- [0..2]] ++
  [[(r,c) | r <- [0..2]] | c <- [0..2]] ++
  [[(i,i) | i <- [0..2]], [(i,2-i) | i <- [0..2]]]

won :: Places -> Bool
won ps = any (\line -> all (`elem` ps) line) winningLines
The list comprehension generates three rows, three columns and two diagonals. Each has exactly three coordinates; therefore all holds precisely when every coordinate of that line is occupied by this player. Taking any over the eight lines proves the win test correct.

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