 Solution

ID: past-exam-of-the-year-2-of-the-earth-sciences-geology-course-of-the-university-of-oxford/2023/paper-1/6/g/solution

Now reset the incident medium to sandstone; the new incident P wave has

p = sin 2 0^{\circ} /2000

. Its reflected S wave has

sin r_{S} = \frac{1200}{2000} sin 2 0^{\circ}, r_{S} = 11.8 4^{\circ} .

The equal result to part (d) follows from the equal ratio

V_{S} / V_{P} = 0.6

in the two incident layers.

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