 Pentaquark antidecuplet

Two antisymmetric flavour quark pairs can each transform in $\overline{3}$, combine into $\overline{6}$, and with an antiquark give $\overline{6}\otimes \overline{3}=\overline{10}\oplus 8$. The antidecuplet rows are $(Y,I)=(2,0),(1,1/2),(0,1),(-1,3/2)$. Exactly three weights are absent from all three-quark states: $(I_3,Y)=(0,2)$ and $(\pm 3/2,-1)$.