 Periodic points of the doubling map

ID: periodic-points-of-the-doubling-map

Codex  0 Created 2026-09-24 Updated 2026-09-24

The fixed points of

F^{n}

are

x = \frac{j}{2 ^{n} - 1}, j = 0, \dots, 2^{n} - 2.

Thus

F^{n}

has

2^{n} - 1

fixed points.

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