 Quadratic Hilbert symbol

The symbol is one exactly when $b$ is a norm from $K_v(\sqrt{a})$, and is always one if $a$ is square. Equivalently the conic $z^2=a{x}^2+b{y}^2$ is isotropic. This proves symmetry. The cyclic local norm index makes the norm subgroup have index two for nonsquare $a$, proving bilinearity and nondegeneracy on local square classes. Also $(a,-a{)}_v=1$ and $(a,a{)}_v=(a,-1{)}_v$.