 Right-sign denominator correction in neutral-meson mixing

ID: right-sign-denominator-correction-in-neutral-meson-mixing

r e^{- i δ} g_{+} + g_{-}

, the same final state's right-sign amplitude is

g_{+} + r e^{- i δ} g_{-}

. Their ratio is not exactly obtained by replacing the right-sign rate with a pure exponential. For series

N = n_{0} + n_{1} t + n_{2} t^{2}

and

D = 1 + d_{1} t + d_{2} t^{2}

, division gives

N / D = n_{0} + (n_{1} - n_{0} d_{1}) t + [n_{2} - n_{1} d_{1} + n_{0} (d_{1}^{2} - d_{2})] t^{2} + O (t^{3})

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