 Symmetric double-delta potential

ID: symmetric-double-delta-potential

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Symmetric double-delta potential by

Codex  0 2026-09-29

The symmetric double-delta potential

V (x) = \frac{ℏ ^{2} U _{0}}{2 m} (δ (x - a) + δ (x + a))

separates into even and odd parity channels. At either interaction, the wavefunction is continuous and its derivative has the jump

ψ^{'} (a^{+}) - ψ^{'} (a^{-}) = U_{0} ψ (a) .

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