Chain maps are chain homotopic when maps satisfy
For a cycle , is a boundary, so on homology.
Fix a vertex of and define the cone operator by adjoining to an oriented simplex, with zero when it is already present. The simplicial boundary formula gives
on the reduced chain complex. Thus its identity is null-homotopic and
for every ; equivalently, and higher homology vanishes.
For the 2-skeleton of ,
It is connected and simply connected, so and . Euler characteristic then gives
For , no vertex or edge is fixed. The only invariant 2-simplex is , on which the 3-cycle preserves orientation, so the chain traces are . The Lefschetz trace formula gives
therefore
If and are coprime, every divisor of is uniquely with and . Hence, for a multiplicative arithmetic function ,
The Möbius function is if a prime square divides , and if is a product of distinct primes. The Euler totient function counts residues modulo coprime to . From the prime factorizations,
Both sides of the second identity are multiplicative, and at a prime power ,
Therefore
Maschke's theorem says that every invariant subspace of a finite-dimensional complex representation of a finite group has an invariant complement. Average any projection over the group to make it equivariant. Induction on dimension therefore decomposes every representation into irreducibles.
The character of a representation is . For a -set , the permutation representation has basis , and its character is the number of fixed points:
For the regular action,
The multiplicity of an irreducible is the character inner product
so
If , Schur lemma gives
For , this is .
Now suppose off the identity. The multiplicity of in is
Thus is a nonnegative integer and is that many copies of the regular representation. Finally,
so

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