Abel integral equation of fractional order 2026-10-20
For an absolutely continuous with , this causal Abel integral equation has inversionUnder Laplace-transform growth hypotheses, the convolution theorem for Laplace transforms converts the original kernel into . Since , the transformed inverse is , giving the formula. It also holds locally in the corresponding integrable convolution class: convolving the two power kernels produces the constant by the beta-gamma identity, so substitution recovers . The same convolution identity proves uniqueness in that class. For example gives .
For the isotropic Jeans-Abel mass inversion, let and . The two preceding projections have the same Abel integral equation kernel, givingTheir ratio recovers , and the isotropic Jeans equation givesEquivalently put and . Then : the common stellar luminosity cancels from the inferred mass. Differentiating these singular-kernel integrals is understood through suitable regularity or a nonsingular variable change, not by naively keeping an infinite lower-end boundary term.
The inversion assumes adequate radial coverage, convergence and a smooth spherical equilibrium. In practice derivatives amplify noise and the unobserved outer tail needs treatment or a model. Unknown anisotropy reintroduces a mass–anisotropy degeneracy; the uniqueness just derived is conditional on the explicitly isotropic velocity distribution.
Past exam of the mathematics course of the University of Cambridge 2001 iii Paper 47 7 Solution Created 2026-10-03 Updated 2026-10-14
Let the surface radius be , let denote epicentral angle in radians, and put . The spherical elastic ray invariant gives . Along either radial leg, if is arclength and polar angle in the ray plane,For a turning ray with minimum radius defined by , the outgoing and incoming legs therefore giveThe square-root turning singularity is integrable for a regular turning point.
Introduce the reduced travel timeIts integrand vanishes at the moving lower endpoint, so differentiation gives . Consequentlyon every regular travel-time branch. This is also the endpoint variation of travel time: the tangential endpoint slowness multiplied by the surface radius is . Angles expressed in degrees would introduce the corresponding conversion factor; the displayed equality uses radians.
For Herglotz–Wiechert inversion, assume is strictly increasing so that is single-valued, and set and . The angular integral becomes an Abel integral equation:For any , multiply by and integrate. Interchanging the triangular region givesThe inner integral equals : the substitution reduces it to . Thus the full constructive inversion isThe surface radius and surface slowness fix the normalization. Varying reconstructs radius and speed parametrically; the centre is recovered by a limit when the data extend that far. The calculation assumes smooth regular turning rays and complete branch data, not merely the first arrival at each epicentral angle.
If decreases outwards on an interval, then it increases as a surface ray travels inward through that interval. Such a ray cannot turn there, since turning requires the decreasing inward value of to reach . Rays that penetrate this interval can traverse it and turn deeper, but the map now has several branches. The angular data constrain combinations of those branch contributions, rather than the single function used above. This is a hidden turning-ray zone from nonmonotone spherical slowness. The stated single-valued inversion fails and does not uniquely locate the speed profile in that interval without additional information. Missing turning rays and possible multiple travel-time branches are the obstruction, not a failure of the algebraic Abel-kernel identity.