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Addition of filters on the natural numbers
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Past exam of the mathematics course of the University of Cambridge
/
2014
/
iii
/
Paper 9
/
3
/
iv
/
Solution
Created
2026-10-03
Updated
2026-10-06
View more
Define
D
G
(
A
)
=
{
x
:
A
−
x
∈
G
}
. The proposed
addition of filters on the natural numbers
is
F
+
G
=
{
A
:
D
G
(
A
)
∈
F
}
.
(1)
Because
addition
of
positive integers
stays in
N
,
D
G
(
N
)
=
N
and
D
G
(
∅
)
=
∅
. Thus the
sum
contains the whole
set
and excludes the
empty set
. If
A
⊆
B
, upward
closure
of
G
gives
D
G
(
A
)
⊆
D
G
(
B
)
, so upward
closure
of
F
gives upward
closure
of the
sum
.
Finally, for every
x
,
(
A
∩
B
)
−
x
=
(
A
−
x
)
∩
(
B
−
x
)
.
(2)
The conjunction property for
G
proved in (
i
) consequently gives
D
G
(
A
∩
B
)
=
D
G
(
A
)
∩
D
G
(
B
)
.
(3)
Finite-intersection
closure
of
F
proves the same
closure
for its
sum
. All proper-filter
axioms
hold, so
(iv) is always true
. No
ultrafilter
assumption is needed here.
Total
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:
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