Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 20 7 iii Solution Created 2026-10-03 Updated 2026-10-14
For a presheaf of sets on a topological space , define and . Then the adjoints to constant presheaves on open sets areTo prove the first adjunction, a natural transformation must satisfy by naturality at the inclusion . Hence it is uniquely determined by a function . Every such function defines a natural transformation by this formula, because restriction maps compose. This gives .
For the second adjunction, a natural transformation satisfies , so it is uniquely determined by a function . Every such function defines the remaining components by restriction, giving . Evaluation acts on presheaf morphisms componentwise, so these object assignments are indeed functors. The use of is essential: a constant presheaf of sets has value there, whereas a sheaf has a singleton value there. No sheaf condition is imposed in this question.
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 23 5 c Solution Created 2026-10-03 Updated 2026-10-14
For a categorical presheaf on the open subsets, define the functors on objects byTo prove , a natural transformation must satisfyfor every open , since the restrictions of are identities. Thus it is determined by the function . Conversely such a function defines all by that equation, and the categorical presheaf restriction laws make the components compatible. HenceFor the other adjunction, a transformation is determined by its component , sinceEvery function supplies compatible components by this formula. Therefore , giving the adjoints to constant presheaves on open sets:These are adjoints of the stated constant-presheaf functor, with its value at every open set including the empty one; no sheafification is involved.