Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 32 1 i Solution Created 2026-10-03 Updated 2026-10-14
For the Weierstrass equation of an elliptic curve in this part, , , . HenceThe elliptic-curve discriminant is thereforeEvery prime other than has unit discriminant, so this integral equation gives good reduction. At the valuation is one. An Admissible change of Weierstrass coordinates changes discriminant valuations by a multiple of twelve; consequently no integral model can lower this value to zero. Thus the equation is minimal there and the reduction is genuinely bad, rather than an artifact of a nonminimal model. Explicitly is singular on the reduced affine cubic: both partial derivatives vanish there. The set of bad reduction primes is
Past exam of the mathematics course of the University of Cambridge 2021 iii Paper 125 1 a Solution 2026-09-28
The Weierstrass equation of an elliptic curve over a field has the general formwith nonzero elliptic-curve discriminant. Admissible change of Weierstrass coordinates relates two such equations defining isomorphic pointed curves over :where and .
If , completing the square and translating simplify every equation. Short Weierstrass form isTwo short equations are -isomorphic precisely when, for some ,the isomorphism from the first curve to the second is .