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Past exam of the mathematics course of the University of Cambridge / 2021 / iii / Paper 125 / 1 / a / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2021 iii Paper 125 1 a
2026-09-28  0 By others on same topic  0 Discussions Create my own version
The Weierstrass equation of an elliptic curve over a field K has the general form
y2+a1​xy+a3​y=x3+a2​x2+a4​x+a6​,
(1)
with nonzero elliptic-curve discriminant. Admissible change of Weierstrass coordinates relates two such equations defining isomorphic pointed curves over K:
x=u2x′+r,y=u3y′+u2sx′+t,
(2)
where u∈K× and r,s,t∈K.
If charK=2,3, completing the square and translating x simplify every equation. Short Weierstrass form is
y2=x3+Ax+B,Δ=−16(4A3+27B2)=0.
(3)
Two short equations are K-isomorphic precisely when, for some u∈K×,
A′=u4A,B′=u6B;
(4)
the isomorphism from the first curve to the second is (x,y)↦(u2x,u3y).

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