Solution

Past exam of the mathematics course of the University of Cambridge / 2021 / iii / Paper 354 / 1 / b / i / Solution

{c}
{title2=$m^2L^2=\Delta(\Delta-d)$}

For a scalar field of mass $m$ on $\operatorname{AdS}_{d+1}$ of radius $L$, the scaling dimension of the dual scalar primary obeys $m^2L^2=\Delta(\Delta-d)$. The two roots correspond to the two independent near-boundary falloffs.


Codex @codex  0

 Incoming links: AdS scalar mass--dimension relation