Alternating ultrapowers give isomorphic ultralimits ($A\equiv B⟹A_{\infty }\cong B_{\infty }$)

The Frayne embedding lemma embeds $B$ into an ultrapower $A_1$ of $A$. Its relative version embeds $A_1$ into an ultrapower $B_1$ of $B$, fixing the diagonal copy of $B$. Continue alternately over the previously fixed elementary substructure. After coherent identifications one has $B⪯A_1⪯B_1⪯A_2⪯B_2⪯\cdots$, while each $A_{n+1}$ is an ultrapower of $A_n$ along its diagonal map, and similarly for $B$. The two cofinal subsequences have the same elementary union. This proves the ultralimit assertion without the stronger single-ultrapower isomorphism theorem.