Past exam of the mathematics course of the University of Cambridge 2007 iii Paper 85 3 a Solution Created 2026-10-03 Updated 2026-10-14
Let a finite or compact group act linearly on a real space , and let be a smooth equivariant dynamical system: . Assume . The representation is an absolutely irreducible real representation when its complexification is irreducible; equivalently, every real linear operator commuting with is a scalar multiple of the identity. Consequently the linearization at the trivial branch is . A generic steady-state crossing has and , with stable noncritical directions removed by a centre manifold if this is a reduction of a larger system.
The isotropy group of a vector is . For a subgroup , its fixed-point subspace of a group action is . Its normaliser isThe normaliser preserves , and describes its residual symmetry. A steady-state axial subgroup is an actual isotropy subgroup with .
The equivariant branching lemma states that, under the smoothness, equivariance, absolute irreducibility, and transverse scalar-eigenvalue crossing hypotheses above, each conjugacy class of axial isotropy subgroup gives a branch of nonzero equilibria in its fixed-point line through . The generic leading nonlinear coefficient determines which parameter side the branch occupies and whether it is transcritical-like or pitchfork-like; the theorem does not assert that these branches are stable or exhaust every possible branch. The usual nondegeneracy condition excludes a vanishing leading nonlinear coefficient. Conjugate subgroups produce symmetry-related copies of a branch, rather than new isotropy types.
To explain the dynamical role of the fixed-point subspaces of a group action, if is fixed by , then for every . Thus the vector field is tangent to that subspace, and uniqueness makes it flow invariant. On a fixed-point line one solves a scalar equilibrium equation and determines radial stability. Stability in the full space additionally requires all transverse eigenvalues to be stable. Higher-dimensional fixed-point spaces support their own restricted dynamics and may contain symmetry-constrained connecting orbits.
Finally, the normalizer action determines axial branch parity: if contains an element acting as on the fixed line, its scalar vector field must be odd, so a generic cubic term gives a pitchfork bifurcation. If that residual sign reversal is absent, a quadratic term is permitted and can give a transcritical-like branch. This is why fixed-space dimension alone does not determine either the branch type or its full stability.
Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 78 3 b Solution Created 2026-10-03 Updated 2026-10-14
For the Equivariant branching lemma, assume a generic steady-state crossing after parameter normalization, and nonzero leading nonlinear coefficient on each axial line. The lemma gives an equilibrium branch for each axial subgroup with a one-dimensional real fixed-point subspace of a group action.
For , . Conjugation by supplies the other two coordinate axes. For , . Sign reflections supply all the equal-magnitude diagonals. These isotropy types are not conjugate: their subgroup orders are and . Thus there are two distinct primary axial branch types: coordinate-axis states and equal-magnitude diagonal states.
The global sign reversal belongs to the group and makes the restricted scalar equations odd, so generically each has the form , with . Its two nonzero solutions satisfy on the appropriate parameter side. Symmetry-related solutions belong to the same branch type; their existence does not imply stability or that both types lie on the same side of the crossing.