Bad barrier array for the Rado order ($f(\{m,n\})=(m,n)$)

The barrier in better-quasi-order theory $[\omega {]}^2$ has shifts $\{m,n\}◃\{n,l\}$ for $m<n<l$. Map each pair to the corresponding element of the Rado order. Neither clause of $(m,n){\le }_R(n,l)$ holds: the first coordinates differ, and the second coordinate of the first pair equals, rather than precedes, the first coordinate of the second. Thus this array is bad, although the Rado order is a well-quasi-ordering. It separates better-quasi-ordering from well-quasi-ordering.