Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 152 2 c Solution Created 2026-09-24 Updated 2026-09-25
Take the invariant divisor , whose class is . Its global sections are represented in the Cox ring by and . They have no common zero on , so is basepoint-free. Its Kodaira map isThis is exactly the ruling , and its fibers have divisor class .
Semiample divisor 2026-10-05
A Cartier divisor is semiample if some positive multiple is a basepoint-free divisor, equivalently its divisor line bundle has a globally generated positive power. Such a power defines a Kodaira map with . Semiampleness implies nefness but need not imply ampleness: a fibre divisor of a morphism to a curve is a basic example.