Bialgebra cocycle twist
= Bialgebra cocycle twist
{title2=$n=\bar\gamma*m*\gamma$}
With the convention $m*\gamma=\gamma*n$ and invertible <bialgebra scalar cocycle> $\gamma$ for $n$, the same <coalgebra> has $n=\bar\gamma*m*\gamma$, or equivalently $m=\gamma*n*\bar\gamma$. Thus $n(a,b)=\sum\bar\gamma(a_{(1)},b_{(1)})m(a_{(2)},b_{(2)})\gamma(a_{(3)},b_{(3)})$. Specifying the equation prevents opposite twist conventions from being conflated.