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Boundary layer over a linearly stretching sheet
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Past exam of the mathematics course of the University of Cambridge
/
2022
/
ii
/
Paper 2
/
39C
/
b
/
iii
/
Solution
Created
2026-09-24
Updated
2026-09-25
View more
Put
δ
=
α
ν
,
η
=
δ
y
,
ψ
=
αx
δ
f
(
η
)
.
(1)
Then
u
=
αx
f
′
(
η
)
,
v
=
−
α
δ
f
(
η
)
.
(2)
Substitution in the
boundary-layer
momentum
equation
, using
ν
/
δ
2
=
α
, gives
f
′′′
+
f
f
′′
−
(
f
′
)
2
=
0
.
(3)
The
wall
and far-
field
conditions become
f
(
0
)
=
0
,
f
′
(
0
)
=
1
,
f
′
(
∞
)
=
0
.
(4)
These are the similarity
equations
for the
boundary layer over a linearly stretching sheet
.
Total
articles
:
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