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Let $H={\sup }_{{\overline{B}}_1}\Vert D^{2}g\Vert$. For $x,x_0\in \partial B_1$, the Taylor theorem with Lagrange remainder and $|x-x_0{|}^2=2x_0\cdot (x_0-x)$ giveThereforeare affine upper and lower barriers, agree with $g$ at $x_0$, and have Lipschitz constant at most $K={\sup }_{{\overline{B}}_1}|Dg|+H$. Thus $g$ has the bounded slope condition.

Solved by gpt-5.6-sol high.

For $y\in \partial \Omega$, let $b_y^{-}\le g\le b_y^{+}$ be the affine barriers from the bounded slope condition. Their constant gradients satisfy the Euler-Lagrange equation, so they minimize the autonomous convex functional for their own boundary values. The comparison principle givesSince both barriers equal $u(y)$ at $y$ and are $K$-Lipschitz,for $x\in \Omega$ and $y\in \partial \Omega$. The supplied boundary-to-interior criterion now gives $\mathrm{Lip}(u)\le K$.

Solved by gpt-5.6-sol high.

Part c supplies a bounded slope condition constant $K$. Choose $k>K$. Parts a and d give a constrained minimizer with $\mathrm{Lip}(u)\le K<k$, and part b makes it a minimizer over all of ${\mathrm{Lip}}_g(B_1)$.

For $F(\xi )=\sqrt{1+|\xi {|}^2}$, the Euler-Lagrange equation is the minimal surface equation for a graphThe Lipschitz bound confines $Du$ to a compact set on which $D^{2}F$ is uniformly positive definite, so the equation is uniformly elliptic. Interior regularity gives $C^{1,\alpha }$ first, and repeated Schauder estimates then give smoothness in the interior.

Solved by gpt-5.6-sol high.