Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 34 1 a ii Solution Created 2026-10-03 Updated 2026-10-14
For , define the bounded stopping time on and on . Before time its stopping events are empty, at time the event belongs to , and subsequently it has stopped everywhere. Subtract the assumed mean identity for this from that for the constant stopping time to obtainSince is integrable and -measurable, this is precisely the defining property of conditional expectation giving . Thus the adapted process is a martingale, completing the bounded-stopping-time characterization of a martingale.
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 34 1 a i Solution Created 2026-10-03 Updated 2026-10-14
For a martingale and a stopping time , expand the stopped value using its martingale differences:The event belongs to the filtration . Each summand is integrable and its conditional expectation given is zero. Taking expectations of this finite sum therefore proves for every bounded stopping time. This proves the forward direction of the bounded-stopping-time characterization of a martingale without assuming an optional stopping theorem.