= BRST-exact covariant gauge fixing
{c}
{title2=$\mathcal L_{\rm gf+gh}=s\Psi$}
For a left <left-acting BRST differential> with $sA=Dc$, $s\bar c=b$, $sb=0$, choose $\Psi=\bar c^a(\partial\cdot A^a+\xi b^a/2)$. The <graded Leibniz rule> gives $s\Psi=b\partial\cdot A+\xi b^2/2-\bar c\partial\cdot Dc$. Integrating the auxiliary Gaussian yields $-(\partial\cdot A)^2/(2\xi)-\bar c\partial\cdot Dc$. At $\xi=1$ this is <Feynman gauge>. Opposite antighost or exact-action sign conventions require a corresponding change of fermion.
// Target: relativistic-quantum-field.bigb
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