Maroni invariant 2026-10-14
The difference between the two normalized splitting degrees of the canonical scroll of a trigonal curve measures its imbalance. Since a smooth trigonal curve cannot contain the negative section, its intersection with that section is nonnegative. This gives , and parity gives .
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 21 2 Solution Created 2026-10-03 Updated 2026-10-14
Work over , and let be a smooth projective curve of genus and gonality three. A trigonal curve has a basepoint-free degree-three pencil, giving a finite morphism of degree three. It is not hyperelliptic, so its canonical map is an embedding. Let , including its scheme multiplicities. The complete pencil has , and Riemann-Roch theorem givesThus the quotient of canonical sections evaluated on has dimension two, and spans a line in . This argument includes ramified fibres, rather than treating only three distinct points.
These two-dimensional quotients vary in a globally generated rank-two bundle on . More explicitly, the image ofhas constant rank two by the preceding dimension count, so it is a subbundle. The equality of the rank at every fibre justifies the bundle construction. On global sections it contains every canonical section, and therefore . The Birkhoff–Grothendieck theorem givesGlobal generation forces nonnegative splitting degrees. Since ,The natural map from to is a surjection at every point, since the canonical system has no base points. By projectivization by quotients it gives a map over , with . Its composition with the tautological map of is the canonical embedding of , so is itself a closed embedding. Each fibre of the ruling maps to the spanning line of ; their union is the canonical scroll of a trigonal curve, and the ruling restricts to the given .
Put . Tensoring by identifies the abstract ruled surface with . The section coming from the quotient onto the smaller summand has self-intersection and will be denoted by . In this normalized presentation its tautological class is ; restoring the twist givesThis class gives the scroll map. It is an embedding if . When , it contracts ; thus the printed embedding description needs this positivity qualification. For example, in genus three the ruled model is and its image is ; in genus four the type has a quadric-cone image. In both cases the smooth curve and its canonical image are still described by the construction above.
As a divisor on , the curve meets each fibre in degree three, so for an integer . The scroll formula givesBy adjunction formula and ,Taking degree on uses and gives . ConsequentlyWriting , this is
A divisor with on is basepoint-free when . Indeed, its pushforward along the ruling splits intoif each degree is nonnegative, sections generate these coefficient functions, and the fibre monomials generate at every point. In particular is basepoint-free when . The Bertini smoothness theorem then makes its general member nonsingular, including the equality case, where the general member avoids .
Conversely, if , then , so every effective member contains . Because the canonical scroll has ,The residual system is basepoint-free. Its general member does not contain and intersects it inThus a general divisor in the original system is with intersecting components and is singular at an intersection point. The fixed component occurs exactly once for a general member, since is not forced to contain it. This proves both directions, with the canonical-scroll hypotheses retained:This is also the bound on the Maroni invariant. Merely observing a fixed component would not by itself prove singularity; the positive intersection with its residual divisor is essential.