Past exam of the differential equations 1 course of the University of Oxford 2021 1 c ii Solution 2026-10-25
For , the equation for the characteristic curves isThe two families are therefore and the characteristic projections from part (a), , together with the vertical characteristic . On either region or , the hyperbolic partial differential equation admits the characteristic coordinatesIndeed is constant along the first family, while . Their Jacobian determinant isThe coefficients of the two pure second partial derivatives in these coordinates vanish, and the coefficient of the mixed partial derivative is . Hence they give the hyperbolic characteristic normal form. They also remain regular at , provided .
The alternative , is valid on patches with . On , it is a parabolic partial differential equation away from the fully degenerate origin, so two independent hyperbolic characteristic coordinates are unavailable.