Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 24 4 b iii Solution Created 2026-10-03 Updated 2026-10-06
Put . Because is inaccessible, for every , and is regular. Choose one witness in for every existential formula of this expanded language and every finite parameter tuple for which a witness exists. These are Skolem functions; they can be chosen in the ambient universe even when is not definable inside .
For each , the ranks of all chosen witnesses with parameters from have supremum below : there are fewer than such parameters and only countably many formulas. Choose strictly above those ranks. The limit closure pointsform a club set. At , every existential assertion in with parameters in has a witness in . The Tarski-Vaught test yieldsThus the set of all such elementary levels is unbounded. It is also closed: the union at a limit of increasing elementary levels is an elementary substructure by the elementary chain theorem, and the union of their ranks is with predicate . ThereforeThis is club reflection below an inaccessible cardinal.
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 24 4 c i Solution Created 2026-10-03 Updated 2026-10-06
If is a Mahlo cardinal, its inaccessible ordinals form a stationary set. For any , intersect that set with the club set of elementary levels from club reflection below an inaccessible cardinal. This supplies an inaccessible with the required elementary substructure.
Conversely, take an arbitrary club set and use it as the predicate . In , the sentence asserting that predicate-marked ordinals occur above every ordinal is true. Any inaccessible elementary level therefore satisfies that is unbounded in its ordinals, which are precisely the ordinals below . Since is closed and is a limit ordinal, . The assumed reflection property consequently gives an inaccessible ordinal in every club set. Hence the inaccessible ordinals are stationary and