Conditionally symmetric increments 2026-10-07
A process has conditionally symmetric increments if, for all deterministic and bounded measurable ,Equivalently, the conditional characteristic function of every increment is invariant under changing the sign of its argument. This property is stronger than unconditional symmetry and is different from independent increments. It supplies identities between positive and negative exponential terminal martingales.
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 25 5 a Solution Created 2026-10-03 Updated 2026-10-07
For a deterministic , conditional symmetry makes the conditional characteristic function of invariant under . The bounded real and imaginary parts of the exponential are legitimate test functions. HenceThe right side is a bounded complex martingale. Both sides have continuous versions by the assumptions; equality on rational times and continuity make them indistinguishable. Thus is a martingale on . Complex martingale assertions mean the corresponding assertions for both real and imaginary parts.
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 25 5 e Solution Created 2026-10-03 Updated 2026-10-07
Fix . The given normal distribution and part (d) implyOne can deduce determinism without any moment assumption on the bracket. Put . Taking gives and , so . Therefore almost surely. Applying this at every rational time and using continuity of quadratic variation gives simultaneously for all outside a single null set.
The Lévy characterization of Brownian motion states that a continuous local martingale starting at zero with this bracket is Brownian motion in its filtration. To see the independent-increment conclusion directly, the Itô formula shows that is a martingale on any fixed bounded time interval: it is a local martingale with a deterministic bound on its modulus. ThusThe deterministic conditional characteristic function identifies an increment independent of . Together with the given path continuity and , this proves is Brownian motion.