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Every subset $B$ of a Lebesgue null set is a Lebesgue measurable set and is itself a null set. In fact the same conclusion follows directly from $m^{\ast }(B)=0$, without assuming measurability in advance. For any $A\subseteq \mathbb{R}$, monotonicity of Lebesgue outer measure gives $m^{\ast }(A\cap B)=0$ and $m^{\ast }(A\setminus B)\le m^{\ast }(A)$. ThereforeThe reverse inequality follows from countable subadditivity of Lebesgue outer measure, applied to the union $A=(A\cap B)\cup (A\setminus B)$. This is Carathéodory's criterion, proving measurability. If $B$ is a subset of an outer-null $N$, its outer measure is zero by the same monotonicity. Thus the restriction of outer measure to measurable sets is a complete measure.

If ${\sum }_n{m}^{\ast }(A_n)=\infty$, the required inequality is automatic. Otherwise each $A_n$ has finite Lebesgue outer measure. Fix $\epsilon >0$. By the defining infimum, for each $n\ge 1$ choose a countable interval cover $\{J_{n,k}:k\ge 1\}$ withThe family indexed by $(n,k)\in {\mathbb{N}}^2$ is countable and covers ${\bigcup }_n{A}_n$. Since all lengths are nonnegative, its total length is at most ${\sum }_n{m}^{\ast }(A_n)+\epsilon$. Taking the infimum over covers of the union and then letting $\epsilon \downarrow 0$ givesThis proves countable subadditivity of Lebesgue outer measure directly from interval covers, without assuming that any $A_n$ is measurable.

A subset $E\subseteq \mathbb{R}$ is a Lebesgue measurable set when it satisfies Carathéodory's criterion: for every $T\subseteq \mathbb{R}$,Suppose $m^{\ast }(A)=0$ and let $B\subseteq A$, allowing $B=A$. The monotonicity of Lebesgue outer measure follows directly from covers: every cover of a larger set covers a smaller set. Thus $m^{\ast }(B)=m^{\ast }(T\cap B)=0$, while $m^{\ast }(T\setminus B)\le m^{\ast }(T)$. ConsequentlyThe reverse inequality is countable subadditivity of Lebesgue outer measure applied to $T=(T\cap B)\cup (T\setminus B)$. Equality follows, even if $m^{\ast }(T)=\infty$. Therefore $A$ and every subset $B\subseteq A$ are Lebesgue measurable sets of measure zero. This is the completeness of Lebesgue measure, obtained without presupposing measurability of the outer-null set.