For a prime , the divisor sum defining the real weight is . If , the second term vanishes and the first is one. Thus , while for every integer because is real and the sum is squared.
Put . With the Fourier transform convention in the question, Fourier inversion gives
The function is smooth and has compact support. Using integration by parts times, with zero endpoint terms, proves
Choose an integer to obtain for . In particular every polynomially weighted absolute integral of is finite.
For the double integral, use
Differentiating the second formula gives . absolute convergence from the rapid decay permits Fubini's theorem. The derivative energy constant for a smooth sieve cutoff is therefore
There is no complex conjugate in this integral: the two factors both become , which is real. The constant is positive; in fact the Cauchy-Schwarz inequality applied to gives .
Here is the basic structure of the smooth divisor-square sieve asymptotic, with enough uniform estimates to specify the error. Write and . Expand the square and count multiples of the least common multiple in an arbitrary interval of length :
The sum is effectively restricted to . Each count is , independent of the interval's position, so the total error is .
The Fourier representation of a smooth Selberg weight reads
Hence, with ,
The four local terms correspond to the prime dividing neither divisor, only the first, only the second, or both. This is the Euler product for a smoothed divisor-square correlation. Factor it as
where
The local factors of are when for small fixed . Thus is a holomorphic function near , and evaluating each local factor at zero gives exactly one. Consequently and there.
The pole expansion now yields
when . Integrating the error against the rapidly decreasing transforms gives . The complementary tails are harmless uniformly: absolute values in the original divisor series give
Any prescribed power decay of is available, so these tails and the tails of the limiting kernel are after choosing sufficiently many applications of integration by parts. The same absolute bound justifies the original exchanges of infinite sums and integrals. Using the evaluated double integral,
We conclude, uniformly over all interval locations,
This proof does not assume that the interval starts near the origin.
Finally choose this one fixed smooth cutoff. primes above in contribute one each to the nonnegative weight, and at most primes lie below . Therefore
for all sufficiently large , uniformly in . The bounded range follows by increasing the fixed constant and using the trivial interval bound . Thus the short-interval prime upper bound from a smooth divisor weight is
For a real smooth cutoff supported on with , define . Its sum over any interval of length is , uniformly in the interval location. Here is the derivative energy constant for a smooth sieve cutoff. Expanding the square yields an interval-counting error and an Euler product for a smoothed divisor-square correlation; its zeta function pole provides the main term. Every prime exceeding has weight one, giving the short-interval prime upper bound from a smooth divisor weight.