Past exam of the mathematics course of the University of Cambridge 2004 iii Paper 3 1 iii a Solution Created 2026-10-03 Updated 2026-10-14
For this diamond Lie algebra, every bracket lies in , and each of these three vectors occurs as a bracket. Thus its derived algebra is exactly . Inside that subalgebra the only nonzero bracket is a multiple of , so . Centrality of then gives . HenceIn particular it is a solvable Lie algebra, although its lower central series of a Lie algebra does not terminate: . Solvability does not imply nilpotence.
Semidirect product of Lie algebras 2026-10-14
If is a Lie algebra homomorphism into the derivations of a Lie algebra, the semidirect product has underlying vector space and bracket . The homomorphism and derivation identities ensure the Jacobi identity. The first factor is an ideal; the second is a subalgebra whose action records the twisting. The diamond Lie algebra arises by letting a one-dimensional algebra act on a Heisenberg Lie algebra.
// Target: linear-algebra.bigb