Solution

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Past exam of the mathematics course of the University of Cambridge / 2009 / ia / Paper 3 / 12B / Solution

{title2=$\nabla\cdot$}
{wiki}

For $F=(F_1,F_2,F_3)$ in Cartesian coordinates,
$$
\nabla\cdot F=\partial_iF_i
=\frac{\partial F_1}{\partial x}
+\frac{\partial F_2}{\partial y}
+\frac{\partial F_3}{\partial z}.
$$


Divergence

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