Omit indices of probability zero. The support of a positive operator of every remaining lies within that of , because is a positive sum containing . Thus is finite.
First suppose , so all quantities are finite. Expand the trace definitions of quantum relative entropy:
Therefore Donald's identity is
If the support condition on fails, at least one positive-weight also fails it. The left side and the final term on the right are then , while the first right-hand sum remains finite. The equality is valid in this extended sense, without taking any undefined difference of infinities.
Let . When the relative entropies are finite, expanding their trace definitions gives
Thus Donald's identity is
For every , the support of a positive operator lies in that of , so the first sum on the right is finite in finite dimension. If the support of is not contained in the support of , at least one positive-weight also violates the support condition. Both sides of the identity are then . This extends the conclusion without subtracting infinite quantities.
By Donald's identity, the objective equals
The nonnegativity of quantum relative entropy makes the last term at least zero, with equality exactly when . Hence the unique minimizing density operator is the ensemble average and
For the classical-quantum state , its marginal on has entropy , its marginal on is , and its joint entropy is . Substituting in the definition of quantum mutual information gives
This is the relative-entropy barycenter of a quantum ensemble: the average state minimizes mean distinguishability from the ensemble. Its minimal value is exactly the Holevo quantity.
The ensemble average uniquely minimizes over density operators . Donald's identity separates this objective into a constant plus , and nonnegativity of quantum relative entropy proves the claim. The minimum is the Holevo quantity , equivalently the quantum mutual information of the associated classical-quantum state.