Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 347 1 a Solution Created 2026-10-03 Updated 2026-10-05
Treat each grain as an isolated compact sphere and take its wavelength-independent radiation-pressure efficiency to be . At distance , its mass and radiation-force cross-section areThe inward gravitational force and outward radiation pressure force areThus the opacity per unit dust mass and the dust-grain Eddington limit areTo equal the Eddington luminosity based on electron-scattering opacity, must equal . ThereforeFor fully ionized hydrogen, , and the stated givesUsing for a roughly solar-composition gas instead gives . This composition-dependent normalization should be stated because the problem does not fix it. For a different constant radiation-pressure efficiency, the critical radius is multiplied by .
At , the grain's radiation-pressure coefficient isConsequently, smaller grains experience a net outward force, larger grains remain gravitationally attracted, and critical-size grains have zero net radial force. Grains released at rest are therefore size-sorted into expelled and infalling populations. With an initial inward velocity, an outward force does not guarantee reversal before the grain reaches the hole; trajectories also depend on initial conditions. Gas drag and dust destruction have been omitted from this isolated-grain calculation. Ordinary interstellar grains are much smaller than a centimetre, so their direct radiative acceleration is very strong in this idealized model.