Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 214 3 c Solution Created 2026-10-03 Updated 2026-10-05
Let , and for putEach edge cutset separates from . Adjacent vertices have graph distances from differing by at most one. Hence an edge can cross at most one of these level boundaries, so the edge cutsets are pairwise edge-disjoint. Write ; then .
The Nash-Williams inequality for unit conductances giveswhere the middle inequality is the Cauchy-Schwarz inequality. One can also derive the first inequality directly: every unit flow has signed net flux one through each , so its energy of a flow on that cut is at least ; sum over the disjoint cuts and use the Thomson principle.
Combining with the commute time identity yieldsThe case is trivial. A path graph, with its endpoints, attains equality.