Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 23 2 a Solution Created 2026-10-03 Updated 2026-10-06
Here is the existential common-substructure test for quantifier elimination. Use a first-order language with a constant symbol, as in the applications below, or the usual conventions for empty generated substructures and truth constants. Let be a first-order theory. Suppose that whenever have a common substructure , then, for every quantifier-free formula and every finite tuple ,The condition is symmetric because it applies also with and exchanged. The conclusion is quantifier elimination for : for every first-order formula there is a quantifier-free formula such thatThe common substructure need not itself satisfy , and witnesses are sought in the whole models, not necessarily in . This test is the QET1 version of the common-substructure test for quantifier elimination.