Write for the dual cone, , and for the affine toric variety. This is the variety denoted in the source; the subscripts there refer to the cone of exponents, whereas refers to the cone in .
For a face of a polyhedral cone , define . If is in the relative interior of , nonnegativity on shows that a functional in vanishes on exactly when it vanishes on all of . Hence is a face of . Conversely a face of gives . Every polyhedral face is exposed: the supporting functionals for its containing facets can be added, since they are nonnegative. If , then , so
The same argument applied to proves , using the closed-cone identity . That identity follows from separation of a point outside a closed convex cone. Finally, enlarging makes its annihilator smaller. Thus these maps are inverse order-reversing bijections, proving face duality for polyhedral cones even when is not full-dimensional.
For the given integral exposing functional , we claim
One inclusion is immediate since vanishes on . For the other, let be nonnegative on and test it on finitely many generating rays of . Where vanishes, those rays belong to , so is already nonnegative. On every other ray is positive, so choosing a sufficiently large integer makes nonnegative on all the rays. This proves the claim. The corresponding semigroup algebra identity is
Thus the face chart is an open subvariety.
For a face , the span of monomials with is an ideal: if with , the face property forces both into . Its quotient is , defining the closed subvariety . If , this subvariety lies in .
Conversely, at a point , the exponents with form a semigroup face: a product is nonzero exactly when both factors are. These exponents are precisely the point of the toric lattices of a face of . To see the geometric assertion, choose finitely many monoid generators by the Gordan lemma. The nonzero generators span a cone. If that cone were not a face, a rational nonnegative relation would express a sum of its generators using an omitted generator with a positive coefficient. Clearing denominators and evaluating the corresponding monomials would equate a nonzero product to zero. Conversely, any point of the toric lattice in their cone has a positive integral multiple expressible using them, so its monomial must also be nonzero. This proves the monomial support face of a toric point assertion. If , then and every monomial outside vanishes at , placing in . Therefore, as reduced closed subvarieties,
The assertion concerns the closed set with its reduced structure; a monomial's principal zero subscheme can have multiplicities.
For the intersection assertion, choose integral exposing functionals for . Both are nonnegative on , so . Localization then gives
This uses the dual of the intersection, as printed in the PDF; the TeX's perpendicular symbol in that position is not the correct transcription.
For a general toric fan, the points with a fixed monomial support face form a torus orbit. The nonzero evaluations extend to a character of the lattice generated by that face, and restriction from the ambient algebraic torus is surjective over . Thus the affine calculation yields the orbit-cone correspondence: contains exactly the orbits for faces . The orbit associated to has character lattice , so it is the source's . The same monomial ideal calculation, chart by chart, shows that its closure is
Indeed, inside a chart containing , the closure has exponent face , and its smaller support faces correspond exactly to cones containing .
Fix , as required for its affine chart. If is not contained in , none of the larger cones can be contained in , so is disjoint from . Conversely every orbit outside has a cone not contained in , and it lies in . Consequently the global complement is exactly
Write , , and . The semigroup algebra has basis , , with . The vertex assumption means that is strongly convex, so its dual cone has full dimension. By the Gordan lemma, is finitely generated: choose integral toric cone generators and subtract integer parts of their nonnegative coefficients; the remainder lies in a bounded parallelepiped with only finitely many lattice points. This argument also applies when has lineality space, by including generators in both directions there.
Choose an integral interior point . For every , both and belong to for all sufficiently large integers . Thus . Inverting all monomial generators of gives the group algebra , which becomes after a basis of is chosen. This proves the dense torus of an affine toric variety assertion:
Density follows because the localization of a ring is of a domain. The algebra map from to defines the extended algebraic torus action; on it is ordinary multiplication.
For a face of a polyhedral cone , set . The convex face property ensures that this is an ideal, and quotienting leaves . Hence is a closed subvariety of . Its open algebraic torus consists of points where precisely the monomials with exponent in are nonzero.
To see that these algebraic tori exhaust the points, let be a point of and put . Multiplicativity gives if and only if both . Thus is a semigroup face. It is for a unique polyhedral convex face : among a finite generating set of , take the toric cone spanned by generators nonzero at . A relation expressing a sum with a generator outside this toric cone as a combination of generators inside would, after clearing rational denominators, contradict the displayed multiplicativity property. Therefore the toric cone is a convex face. Conversely, if lies in that convex face, a positive multiple of is an integral sum of those generators, so is nonzero as well. This also proves uniqueness.
The point lies in exactly when its convex face is all of . Therefore
One can equivalently write this as the disjoint union of the open algebraic tori of the proper convex faces. For , the same description shows that exactly when is not in the convex face supporting . On every with the monomial vanishes identically. Consequently the monomial zero locus in an affine toric variety is
This is an equality of reduced subvarieties, or of their underlying closed sets. The principal subscheme itself may have multiplicity, as already shows on .
The face duality for polyhedral cones is the order-reversing pair of maps
Their values are convex faces because the relevant pairings are nonnegative and a sum pairs to zero only if each summand does. More explicitly, finitely many nonnegative exposing functionals can be summed to expose the indicated intersection. For a convex face , choose exposing it: . Then , so , while the reverse inclusion is immediate. Apply the same argument to a convex face of , using , to prove the other composite is the identity. Inclusion reversal follows directly from annihilators. This proves the bijection, not just the existence of the maps.
For , write and . An exposing functional for is strictly positive on every toric ray outside . Small perturbations of within preserve those finitely many strict inequalities, so has nonempty relative interior in and spans it. Therefore generates , by the interior-point argument used above within that subspace. Thus the open algebraic torus of is . Here uses the lattice in the whole annihilator, rather than the toric cone semigroup. The sublattice is a saturated sublattice of and consequently a direct summand; restriction is surjective. The extended algebraic torus action is multiplication on this open algebraic torus and hence transitive. All other monomials vanish there. It follows that
This is the torus orbit-cone correspondence and its orbit closure in a toric variety description. Under convex face duality, .
Finally, choose integral exposing . Localizing at gives : for , adding a sufficiently large multiple of makes it nonnegative on every toric ray of outside , while preserving nonnegativity on . Hence is the usual affine open chart inside . An orbit belongs to it exactly when . The requested complement of an affine toric face chart is therefore
All sets on the right are closed, and if is not contained in , neither is any convex face containing . This justifies replacing the excluded orbits by their whole closures.