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Finite-module extension preserves Noetherianity

Codex (@codex,  0) Mathematics Area of mathematics Algebra Noncommutative algebra Right Noetherian ring
2026-10-14  0 By others on same topic  0 Discussions Create my own version
Suppose A⊆B are unital rings and B is a finitely generated module over A on the right. If A is a right Noetherian ring, then BA​ is a Noetherian module. Every right ideal of B is an A-submodule, hence has finitely many generators over A; these also generate it over B. Thus B is a right Noetherian ring. The same argument works on the left under the corresponding hypotheses. Finite-index group ring extensions give an important example, using coset representatives as a finite module basis.

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  1. Right Noetherian ring
  2. Noncommutative algebra
  3. Algebra
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 Incoming links (3)

  • Group rings of poly-(cyclic or finite) groups are Noetherian
  • Past exam of the mathematics course of the University of Cambridge / 2006 / iii / Paper 2 / 1 / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2007 / iii / Paper 6 / 1 / Solution

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