Cohomology under an affine morphism 2026-10-05
For an affine morphism and a quasi-coherent sheaf on , the direct image sheaf has the same sheaf cohomology on as on . To prove this, take a flasque resolution . Its direct images are flasque sheaves. On each affine open , the complex of sections of the direct images is . By vanishing of quasi-coherent cohomology on an affine scheme, this augmented complex is exact. Checking on the affine basis proves that resolves . Its global sections are identical to those of the original resolution.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 113 3 a Solution Created 2026-10-03 Updated 2026-10-05
First consider the preliminary cohomological facts. The exam's term flabby means flasque sheaf: every restriction map is surjective. For open sets , lift a section of to using the given surjectivity when is flasque. Extend that lift to using the flasque sheaf , then project to . This proves that is a flasque sheaf.
One construction of a flasque resolution starts with the sheaf , with pointwise restriction. It is a sheaf of abelian groups with surjective restrictions, and sending a section to all its germs embeds in it. Repeating on the cokernels constructs an exact sequencewith each flasque. Define sheaf cohomology by the cohomology of the cochain complex of global sections of such a resolution; the groups are independent of the chosen flasque resolution. If is itself flasque, the quotient result just proved makes every successive cokernel flasque. Applying the assumed surjectivity of sections to each successive short exact sequence of sheaves proves exactness of the global-section complex in positive degrees. Thus for .
Now let be the function field of the smooth algebraic curve. Its divisor class group isHere is the discrete valuation of the discrete valuation ring , and consists of the principal divisor elements . These sums have finite support: on a finite affine cover, represent as a fraction of regular functions; each nonzero numerator or denominator has only finitely many zeros on a curve, since a proper closed subset of a Noetherian one-dimensional irreducible space is finite.
For a divisor on an algebraic curve , define the line bundle associated to a divisor byIn this expression the valuation condition applies to nonzero . If is a uniformizer, the stalk is . Shrinking around removes all other zeros and poles of and all other points in the support of , so this also gives an actual local generator. Thus is a locally free sheaf of rank one. Multiplication gives an isomorphismon every stalk. If , then , so the construction factors through a homomorphism .
It is injective: if is trivial, an isomorphism from supplies a nonzero global rational generator . At each closed point, generates , giving , hence .
It is surjective: take a line bundle and a nonzero rational section , obtained by choosing a frame on any nonempty trivializing open set. If is a local frame, write with . Since changes of frame are units, is independent of the frame near . A finite trivializing cover shows that these numbers have finite support. Set . The map gives , because at the condition is exactly regularity of . Replacing by changes by , so this construction is well defined on classes. This proves the divisor class group and Picard group of a smooth curve identification
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 113 4 Solution Created 2026-10-03 Updated 2026-10-05
The resolution principle for sheaf cohomology states that an exact sequencewith for every computes as the cohomology of . In particular one may use a flasque resolution.
An affine morphism is one for which the inverse image of every affine open subset of is affine. We use vanishing of quasi-coherent cohomology on an affine scheme: a quasi-coherent sheaf has zero higher sheaf cohomology on an affine variety. Take a flasque resolution . Each direct image sheaf is flasque, because restriction on is restriction on . On an affine open , the augmented complex of sections isIts positive-degree cohomology vanishes by the affine theorem, and its degree-zero kernel is . Checking exactness on this affine basis shows that is a flasque resolution of . The global-section complexes are identical, proving cohomology under an affine morphism:
For projective space, put with its usual grading and . Construct the twisting sheaf on projective space by setting its sections on to be the degree- part , viewed as a module over . It is free of rank one with generator , even when is negative. On overlaps the generators differ by the unit , so these modules glue to a line bundle .
Assume first . These local modules all embed in the graded fraction field, and agreement on overlaps identifies global sections with . Since is a unique factorization domain and at least two distinct variables occur, a reduced fraction belonging to every has no nonconstant denominator. Thus the intersection is . Counting monomials by stars and bars givesHere . The printed formula needs the convention that a counting binomial coefficient is zero when its upper integer is smaller than its nonnegative lower integer; the generalized polynomial convention for negative upper integers would give incorrect dimensions. For , every twist on the single point is trivial, so for every and its higher cohomology is zero. This case supplies the base of dimension induction; the displayed top-cohomology formula below is for .
The standard affine opens have affine finite intersections. The acyclic cover theorem and affine vanishing identify sheaf cohomology with a Čech cochain complex ending in degree . In particular for .
Let , with inclusion . Multiplication by gives the hyperplane exact sequence for twisting sheavesExactness is checked in the local trivializations, where a hyperplane equation is a non-zero-divisor and the quotient is its restriction to . Since a closed immersion is an affine morphism, the first part identifies the cohomology of with that on .
For , the long exact sequence in sheaf cohomology and giveStarting from the given vanishing for sufficiently large and descending gives for and for .
Now let , and assume the formulas in dimension . Restrictionis surjective for every : for it is polynomial restriction, and for both groups are zero since . The long exact sequence in sheaf cohomology therefore makes injective. For , dimension induction gives , so the same sequence makesinjective. Composing these injections up to a sufficiently large twist, where the target is zero by the given hypothesis, proves for every and .
The remaining part of the long exact sequence in sheaf cohomology is consequentlywhere the last zero uses the affine-cover dimension bound on . Hence . Using dimension induction and eventual vanishing, downward summation yieldsby telescoping Pascal's identity; for it is zero. Thus, without invoking Serre duality in the induction,Finally, the canonical bundle of projective space is , obtained by taking determinants in the dual Euler sequence. Serre duality therefore predictsIt pairs the two computed extreme-degree dimensions and pairs zero intermediate groups with zero intermediate groups, exactly as required.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 118 2 a Solution Created 2026-10-03 Updated 2026-10-05
Choose a flasque resolution of the sheaf of abelian groups ,A flasque sheaf has surjective restriction maps; such resolutions exist for every sheaf of abelian groups. Apply the global section functor to obtain a cochain complex. The sheaf cohomology groups areFor , the denominator is zero and . Different resolutions give canonically isomorphic groups; the resolution principle for sheaf cohomology is what permits other acyclic resolutions to compute these same groups.
Resolution principle for sheaf cohomology 2026-10-05
If is an exact sequence of sheaves of abelian groups on and for every and , then sheaf cohomology is computed by the cochain complex of global sections:In particular a flasque resolution computes sheaf cohomology. Acyclicity is required on the space on which cohomology is being computed.